binary search

int B(int a[],int f, int l, int t)
{
 if( f > l)// 1st Base Case, return if the array is empty
 {
  return -1;
 }
 int mid = (f+l)/2;
 if(a[mid] == t) // found the target
  return mid;
 else if(t >n)
 r = B(c,0,9,n);
 if( r == -1)
  cout<<" Sorry !!! The Elemen Is not in our Array ... "<<endl;
 else
  cout<<" Your element is in the index : "<<r<<endl;
}

#include <stdlib.h>
#include <string.h>
int bisearch(void *sorted, const void *target, int size, int esize, int
   (*compare)(const void *key1, const void *key2)) {

int                left,
                   middle,
                   right;
                                                                            
// Continue searching until left = right                                                                                            

left = 0;
right = size - 1;
while (left <= right) {
   middle = (left + right) / 2;
   switch (compare(((char *)sorted + (esize * middle)), target)) {
      case -1:  
      //  search   the right of the middle index.                 
      left = middle + 1;
      break;
      case 1:
      //  search  the left of the middle index.
      right = middle - 1;
      break;
      case 0:
       return middle;
   }
}
 // not found
return -1;
}