convert char(number) to required unsigned char

passionpatel

Given For e.g,
char input[] = "10011210582553796";

now Hexadecimal of 10011210582553796 is 2391249A8B74C4.

So output unsigned char* should have value,
unsigned char output[8] = {0x00,0x23,0x91,0x24,0x9A,0x8B,0x74,0xC4};

Any solution to convert given input char* to output char* with above mentioned requirement?

code should run on platform for which __int64/signed long long is not supported.

Thanx in advance...

DrRakha

To convert from the decimal number system into hex number system .A way to do that , first convert the number you binary and from binary take every 4 digits and make 1 digit hex ,

example : 12 )decimal to 01010)binary to C ) hex

passionpatel

The number i have given is out of range of int datatype, so can not use printf or atoi operation which are supported for int datatype. Actually number can be stored in int64 type but system does not support int64 datatype. So i want to convert is to unsigned char output[8] = {0,35,145,36,154,139,116,196} = {0,0x23,0x91,0x24,0x9A,0x8B,0x74,0xC4}
Even i cannot use left shift or right shift (multiplication/devision) when number reaches above integer capacity.

passionpatel

found solution

Code:

     int number = 0;
     char numberchars[] = "10011210582553796";
     int i = 0;
     int ans = 0;
     int carry = 0;

     char answerArray[100] = {0};

     char remainderArray[100] = {0};
     int remindex = 0;
     int ansindex = 0;
     int remainder = 0;

     while( numberchars[i] != '\0' )
     {
          while( numberchars[i] != '\0' )
          {
               char currentchar[2] = {0};
               currentchar[0]=numberchars[i];

               int num = atoi(currentchar);
               num += remainder;
               remainder = 0;

               if ( num < 2  )
               {               
                    remainder = num;
                    if(i>0)
                         answerArray[ansindex++] = '0';
               }
               else
               {
                    remainder = num % 2;
                    int answer = num / 2;

                    char a[2] = {0};
                    itoa(answer,a,10);

                    answerArray[ansindex++] = a[0];
               }

               i++;
               remainder *= 10;
          }

          char a[2] = {0};
          int rval = remainder / 10;
          itoa(remainder / 10,a,10);
          
          remainderArray[remindex++] = a[0];
          int size = sizeof(answerArray);
          memcpy(numberchars,answerArray,sizeof(answerArray));
           size = sizeof(answerArray);
          memset(answerArray,0,sizeof(answerArray));
          ansindex = 0;
          remainder = 0;
          i=0;
     }

     char int64[8] = {0};

     for(int k=0;remainderArray[k]!= '\0';k++)
     {
          int64[7-(k/8)] |= ((remainderArray[k]-'0') << (k%8));
     }

DrRakha

thank you so much for posting the solution :gOOd:

Java

C/C++

PHP

C#

HTML

CSS

ASP

Javascript

JQuery

AJAX

XSD

Python

Matlab

R Scripts

Weka

convert char(number) to required unsigned char

Topic Tags

Java

C/C++

PHP

C#

HTML

CSS

ASP

Javascript

JQuery

AJAX

XSD

Python

Matlab

R Scripts

Weka

convert char*(number) to required unsigned char*

Topic Tags

convert char(number) to required unsigned char