what is the output of this program and how it be?

saics

Hi friendzz..Can any body tell me the output of this program and explain how it came....and also how these operations (p+p[3]-p[1] ) performed

Code:

#include<stdio.h>
#include<conio.h>
void main()
{
char  c[]="GATE2011";
char *p=c;
clrscr();
printf("%s",p+p[3]-p[1]);
getch();
} 

saics

Is there Any body to explain this.....k ivl give the output, plz i need explanation how this output came?

output is : 2011

DrRakha

%s used to print a string of characters .

i didn't run this app, but it seems this p[3]-p[1] part removed the First part of the string . are you sure that the output is 2010 or G2011

saics

sure it's 2011 (check once if possible)...
but i need hw this output came i.e. what operations takes place here on p...whether it performs on p's address or ascii values of "p" or any other...

hseldon

This code is equivalent to

Code:

p + (69 - 65)

where 69 is the decimal equivalent of 'E' (p[3]) and 65 is the decimal equivalent of 'A' (p[1])

pyromaniac

Statement will be: (as written above)
p+(69-65)

For example, if the code is as follows:
printf("%s",p+1);

output will be "ATE2011"

Similarly for
printf("%s",p+2);

output will be "TE 2011"

ASCII values of A(p[1]) and E(p[3]) are 69 and 65 respectively, so it will be "p+(69-65)" and the output will be "2011"

saics

thanku bro...i think it is ascii value not decimal value...

saics

pyromaniac wrote:

Statement will be: (as written above)
p+(69-65)

For example, if the code is as follows:
printf("%s",p+1);

output will be "ATE2011"

Similarly for
printf("%s",p+2);

output will be "TE 2011"

ASCII values of A(p[1]) and E(p[3]) are 69 and 65 respectively, so it will be "p+(69-65)" and the output will be "2011"

thank u dude...but p contains the address of the string....but how it can store ascii value in p[1] and p[3]...??

smithon56

its 2011 as per my knowledge
.....

alexsmth114

Highly informative post, thanks u for sharing!!..

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what is the output of this program and how it be?