Type Conversion

convert from type to type in C++
cpp code

/*
 * Type conversion games.  
 */
#include <stdio.h>

main()
{
        /* Meaningless numbers. */
        short s = -41;
        int i = 9;
        double d = 4.27;
        double ld = 4983.22;
        long l = 17;
        long long ll = 170;
        unsigned ui = 48;

        /* When using printf, you must specify the size for items longer
           than int or double.  Many incorrect combinations work anyway,
           but it's a good idea to get it right. */
        printf("A: %d %ld %lld %f %lf\n", i, l, ll, d, ld);

        /* Operators generally convert to the longer type, but you can
           force other conversions with casts. */
        printf("B: %f %d %d %f %f\n", 
               i * d, 
               i * (int)d, 
               i / 12,
               i / 12.0,
               (double)i / 12);

        /* Conversion will convert to the left type. */
        i = d;
        d = s;
        printf("C: %d %f\n", i, d);

        /* Unsigned values can be printed with the u conversion.  It generally
           differs from %d only for large numbers. */
        printf("D: %u\n", ui);

        /* Constants can be appended with a letter to give them the
           associated type.  This generally matters only when the 
           constant you want won't fit into the unmodified length. */
        l = 1598L;
        ll = 9081092830129ll;    /* Maybe LL would be better than ll. */
        ld = 49.3981273394L;
        printf("F: %ld %lld %.12lf\n", l, ll, ld);

        /* Converting from a longer to a smaller size will also produce
           junk if the value does not fit. */
        i = 8000000;
        s = i;
        printf("G: %d == %d (sort of)\n", i, s);
}

convert from type to type in C++