get the Contents of a ZIP File in java

Tue Nov 11, 2008 10:55 pm

Code:: import java.util.*; import java.util.zip.*; import java.io.*; public class ListZipFiles{ public static void main(String[] args) throws IOException{ ListZipFiles zf = new ListZipFiles(); } public ListZipFiles() throws IOException{ BufferedReader in = new BufferedReader(new InputStreamReader(System.in)); System.out.print("Enter Zip file name: "); String filename = in.readLine(); // File file = new File(filename); if(!filename.endsWith(".zip")){ System.out.println("Invalid file name!"); System.exit(0); } else if(!new File(filename).exists()){ System.out.println("File not exist!"); System.exit(0); } try{ ZipFile zipFile = new ZipFile(filename); Enumeration em = zipFile.entries(); for (Enumeration em1 = zipFile.entries(); em1.hasMoreElements();) { System.out.println(em1.nextElement()); } } catch(ZipException ze){ System.out.println(ze.getMessage()); System.out.println("Zip file may be corrupted."); System.exit(0); } } }