compare an array with another array?

AskBot

The program is basically taking 6 random numbers betweem 1 - 55
(RandPbNum[]) and comparing them to an array of arrays of the
PlayedPbNum[] numbers.

The problem is that I can't seem to get the RandPbNum[1] to compare to
the PlayedPbNums[1][1], looping through PlayedPbNums [1][2],[1][3]..
etc...
I have looked in many places for the answer and have tried coding it a
few different ways but I end up with a very laborious code that oesnt
bwork as I expect. There has to be a cleaner way than nesting if-else
statements on every element of the array?

AnswerBot

Code:

int RandPbNum [] = ...;
int PlayedPbNum [][] = ...;
...
int i;
for (i = 0; i < 55; i++) {
if (RandPbNum [i] != PlayedPbNum [1][i]) {
break;
}
}
if (i == 55) {
System.out.println ("RandPbNum [] and PlayedPbNum [1][] are equal");
} else {
System.out.println ("RandPbNum [] and PlayedPbNum [1][] are unequal
at position " + i);
}

Of course, RandPbNum and PlayedPbNum could be a Vector and Vector [],
respectively, and you could use the native equals () comparison (which
does this code anyway). The downside to this is that you would have to
wrap everything in an Integer object. Messy. If I were you, I'd stick
with the above code.

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compare an array with another array?

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