Overriding Equals Method

Wed Oct 22, 2008 2:07 am

I have a doubt. When I compile and run this program, it gives the o/p
True
9
8.
Actually this program is creating 2 objects of same type with 2 different
parameters (8 and 9) and comparing the 2 objects with overridden Equals method.
Could anyone please explain me, why "this.moofValue" is getting the value "8"
when it actually passes "9". (line marked XXX)

Thanks & Regards

Chooti Baba.

Code:: public class EqualsTest { public static void main (String [] args) { Moof one = new Moof(8); Moof two = new Moof(9); if (one.equals(two)) { System.out.println("one and two are equal"); } } } class Moof { private int moofValue; Moof(int val) { moofValue = val; } public int getMoofValue() { return moofValue; } public boolean equals(Object o) { System.out.println(o instanceof Moof); System.out.println(((Moof)o).getMoofValue()); System.out.println(this.moofValue); //XXX if ((o instanceof Moof) && (((Moof)o).getMoofValue() == this.moofValue)) { return true; } else { return false; } } }

Wed Oct 22, 2008 2:08 am

Hi,

you are getting this.moofValue as 8 because, you are calling the
equal method on the Object one, which has a value of 8. If you
reverse the caller and the argument in equals method, say :
if( two.equals(one)) .... then you will get the result as you wanted,
i.e. value 9 on the calling object.

Overriding Equals Method

Overriding Equals Method

Re: Overriding Equals Method

Topic Tags