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Unmarshall From XML using JAXB :

This is example unmarshall the content of Student xml into the java objects .
java code
import jaxbclasses.studentType;
import java.io.File;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBElement;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;

public class UnmarshallingTest {

    public static void main (String [] args) {
        try {
            JAXBContext jc = JAXBContext.newInstance ("jaxbclasses");

            Unmarshaller u = jc.createUnmarshaller ();

           File f = new File ("student.xml");
           JAXBElement element = (JAXBElement) u.unmarshal (f);

           studentType student= (studentType) element.getValue ();
           System.out.println ("Student Gender is  : " + student.getGender ());
           System.out.println ("Student Name is : " + item.getName ());
           System.out.println ("Student Age is : " + item.getAge ());
       } catch (JAXBException e) {
           e.printStackTrace ();
       }
   }
}
 


Here is the schema ( XSD file ) .
xml code
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <xsd:element name="student" type="studentType"/>
    <xsd:complexType name="studentType">
        <xsd:sequence>
            <xsd:element name="gender" type="xsd:string"/>
            <xsd:element name="name" type="xsd:string"/>
            <xsd:element name="age" type="xsd:integer"/>
        </xsd:sequence>
    </xsd:complexType>
</xsd:schema> 




_________________
M. S. Rakha, Ph.D.
Queen's University
Canada


Author:
Mastermind
User avatar Posts: 2715
Have thanks: 74 time

For this message the author DrRakha has received gratitude : manniar

I think there is a small typo in your example,

I think the code should read,
java code
System.out.println ("Student Name is : " + student.getName ());
System.out.println ("Student Age is : " + student.getAge ());


Also it might be worth mentioning that you need to generate the java class from the XSD file you've mentioned. I used the utility plug-in for Eclipse called XJC. Then the code in your example will find the java class for StudentType. Might be obvious for experienced programmers but not for people new to Jaxb.

Good example though, thanks.



Author:
Newbie
User avatar Posts: 1
Have thanks: 1 time

For this message the author robbie70 has received gratitude : DrRakha
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Topic Tags

Java XML, Java JAXB






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