Using firebug with JQuery

Thu Jan 10, 2013 12:17 pm

Logging into Firebug console from JQuery, note you must have Firebug installed at your browser.
javascript code

<html>
<head>
<title>Using firebug with JQuery</title>
 
<!--
 <script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js">
</script>
 Note you can download the JQuery package instead of using Google version. --> 
<script src="jquery-1.8.3.js"></script>

<script>
    $(document).ready(function(){
  $("button#btn1").click(function(){
    
	$.enableConsole = false;
$.fn.console = $.console = function(method){
	if (window.console && console[method] && $.enableConsole)
		console[method].apply(this, [].splice.call(arguments,1))
	return this;
}
// See console
$.enableConsole = true;  

//  calling firebug functions, here we use console functions 
$.console('debug', 'Am debuging my code with firebug', 'debugging');

// Use firebug console chain function easily:
var color = 'yellow';
$('#divEnd').css('color', color).console('log', 'Setting font color to ', color);

// And the access to the other functions time and timeEnd
$('#divEnd').console('time', '1000').animate('message').console('timeEnd', '3000');
 
  }); 
  }); 
</script>
</head>
<body>
 
<div id="divEnd"  style="background:#0414F4;color:white;width='100';">Content Here.</div>
<button id="btn1">Start Using Firebug</button>
</body>
</html>