Listing the Contents of a Directory

Code:

<html>
<head>
<title>Listing the contents of a directory with readdir()</title>
</head>
<body>
<?php
$dirname = "./";
$dh = opendir( $dirname );
while ( gettype( $file = readdir( $dh )) != boolean ){
   if ( is_dir( "$dirname/$file" ) )
       print "(D)";
   print "$file<br>";
}
closedir( $dh );
?>
 </body>
</html>

_________________
M. S. Rakha, Ph.D.
Queen's University
Canada

Author: DrRakha
Mastermind

Posts: 2715
Have thanks: 74 time

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